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y = ax^(n+1) + bx^(-n): find x^2 d2y/dx2

The same question, asked 2 times: 10 May 2023 S1, 19 Apr 2025 S1. Every wording below, oldest first.

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  1. Question 1

    10 May 2023 S1

    138
    If y=axn+1+bx−ny=ax^{n+1}+bx^{-n}, then x2d2ydx2=x^2\frac{d^2y}{dx^2}=

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  2. Question 2

    19 Apr 2025 S1

    133
    For n∈Nn \in\mathbb{N} if y=axn+1+bx−ny= ax^{n + 1}+ bx^{- n}, then x2 d2y dx2=x^{2}\frac{{\text{ }d}^{2}y}{\text{ }dx^{2}}=

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