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Derivative of a variable power f(x)^g(x) by taking logarithms

This type of question, asked 9 times: 11 May 2023 S2, 20 Apr 2025 S1, 20 Apr 2025 S2, 22 Apr 2025 S2, 20 Apr 2026 S1, 13 May 2026 S2, 14 May 2026 S1, 14 May 2026 S2, 15 May 2026 S1. All 10 questions below, oldest first.

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  1. Question 1

    11 May 2023 S2

    148
    If y=(sin⁡x)tan⁡xy=(\sin x)^{\tan x}, then dydx\frac{dy}{dx} is equal to

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  2. Question 2

    20 Apr 2025 S1

    138
    If y=xx+x1xy=x^{x}+x^{\frac{1}{x}}, then dydx\frac{dy}{dx} is equal to

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  3. Question 3

    20 Apr 2025 S2

    139
    If xy+yx=abx^{y}+y^{x}=a^{b}, then dydx\frac{dy}{dx} at x=1,y=2x= 1,y= 2 is

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  4. Question 4

    22 Apr 2025 S2

    131
    Derivative of x(xx)x^{\left( x^{x} \right)} is

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  5. Question 5

    20 Apr 2026 S1

    72
    If y=(x2+1)sin⁡xy = (x^2 + 1)^{\sin x} for x>0x > 0 such that dydx=y[2xsin⁡xg(x)+cos⁡x⋅log⁡[g(x)]]\dfrac{dy}{dx} = y\left[\dfrac{2x\sin x}{g(x)} + \cos x \cdot \log[g(x)]\right], then the function 1g(x)\dfrac{1}{g(x)} is...

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  6. Question 6

    13 May 2026 S2

    72
    If y=2x+(sin⁡x)xy = 2^x + (\sin x)^x, then dydx=\dfrac{dy}{dx} =

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  7. Question 7

    13 May 2026 S2

    74
    If xy⋅yx=1x^y \cdot y^x = 1 then the value of dydx\dfrac{dy}{dx} is

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  8. Question 8

    14 May 2026 S1

    72
    If y=xxy = x^{\sqrt{x}}, then dydx=\dfrac{dy}{dx} =

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  9. Question 9

    14 May 2026 S2

    74
    If xyyx=1x^y y^x = 1, then dydx\dfrac{dy}{dx} is equal to

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  10. Question 10

    15 May 2026 S1

    75
    If y=(log⁡x)log⁡xy = (\log x)^{\log x} and dydx=yx×f(x)\dfrac{dy}{dx} = \dfrac{y}{x} \times f(x) then f(x)=…f(x) = \ldots

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