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Second derivative of x with respect to y (d2x/dy2)

This type of question, asked 5 times: 11 Apr 2026 S2, 13 Apr 2026 S1, 20 Apr 2026 S2, 12 May 2026 S1, 13 May 2026 S1. All 5 questions below, oldest first.

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  1. Question 1

    11 Apr 2026 S2

    72
    If x3+y3=6x^3 + y^3 = 6 and d2ydx2⋅d2xdy2=m(xy)n\dfrac{d^2y}{dx^2} \cdot \dfrac{d^2x}{dy^2} = \dfrac{m}{(xy)^n}, where m,n∈Rm, n \in R then mn=\dfrac{m}{n} =

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  2. Question 2

    13 Apr 2026 S1

    72
    If y=x+exy = x + e^x, then d2xdy2\dfrac{d^2x}{dy^2} is equal to

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  3. Question 3

    20 Apr 2026 S2

    73
    If x=4t3+3,y=3t4+4x = 4t^3 + 3, y = 3t^4 + 4 and d2xdy2(dxdy)n\dfrac{\frac{d^2x}{dy^2}}{\left(\frac{dx}{dy}\right)^n} is constant then the value of nn is

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  4. Question 4

    12 May 2026 S1

    71
    If x=at2x = at^2 and y=2at,t≠0y = 2at, t \neq 0 then ...

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  5. Question 5

    13 May 2026 S1

    73
    If y=x−exy = x - e^x, then d2xdy2=…\dfrac{d^2x}{dy^2} = \ldots

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