PYQ Vault

Integral of e^(2x)(sin 2x cos 2x - 1)/sin^2 2x

The same question, asked 2 times: 22 Apr 2025 S2, 13 Apr 2026 S1. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    22 Apr 2025 S2

    142
    ∫e2x(sin⁡2x cos⁡2x−1)sin⁡22x dx=\int e^{2x}\dfrac{(\sin2x\,\cos2x-1)}{\sin^{2}2x}\,dx=

    Tap an option to check your answer.

  2. Question 2

    13 Apr 2026 S1

    79
    ∫e2x2(sin⁡2xcos⁡2x−1)2sin⁡22x dx=Ae2xcot⁡2x+c\displaystyle\int e^{2x}\dfrac{2(\sin 2x\cos 2x - 1)}{2\sin^2 2x}\,dx = Ae^{2x}\cot 2x + c (Where c is the constant of integration.), then A3=A^3 =

    Tap an option to check your answer.