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Integral of sin x / sin 4x

The same question, asked 2 times: 11 Apr 2026 S2, 17 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    11 Apr 2026 S2

    77
    ∫sin⁡xsin⁡4x dx=\displaystyle\int\dfrac{\sin x}{\sin 4x}\,dx =

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  2. Question 2

    17 Apr 2026 S2

    77
    If ∫sin⁡xsin⁡4x dx=αlog⁡∣1+sin⁡x1−sin⁡x∣+βlog⁡∣1+2sin⁡x1−2sin⁡x∣+c\displaystyle\int\dfrac{\sin x}{\sin 4x}\,dx = \alpha\log\left|\dfrac{1 + \sin x}{1 - \sin x}\right| + \beta\log\left|\dfrac{1 + \sqrt{2}\sin x}{1 - \sqrt{2}\sin x}\right| + c, then the value of 32(α+β2)=32(\alpha + \beta^2) =

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