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Integral of e^x [f(x) + f'(x)] where f is a trigonometric or log function

This type of question, asked 6 times: 3 May 2023 S2, 10 May 2024 S2, 22 Apr 2025 S2, 13 Apr 2026 S1, 14 May 2026 S2, 15 May 2026 S1. All 6 questions below, oldest first.

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  1. Question 1

    3 May 2023 S2

    144
    The value of ∫ex1−sin⁡x1−cos⁡x dx\int e^{x}\frac{1-\sin x}{1-\cos x}\,dx is equal to

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  2. Question 2

    10 May 2024 S2

    125
    ∫ex(1−cot⁡x+cot⁡2x) dx=\displaystyle\int e^x(1-\cot x+\cot^2 x)\,dx =

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  3. Question 3

    22 Apr 2025 S2

    142
    ∫e2x(sin⁡2x cos⁡2x−1)sin⁡22x dx=\int e^{2x}\dfrac{(\sin2x\,\cos2x-1)}{\sin^{2}2x}\,dx=

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  4. Question 4

    13 Apr 2026 S1

    79
    ∫e2x2(sin⁡2xcos⁡2x−1)2sin⁡22x dx=Ae2xcot⁡2x+c\displaystyle\int e^{2x}\dfrac{2(\sin 2x\cos 2x - 1)}{2\sin^2 2x}\,dx = Ae^{2x}\cot 2x + c (Where c is the constant of integration.), then A3=A^3 =

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  5. Question 5

    14 May 2026 S2

    80
    Evaluate ∫ex(sin⁡x+2cos⁡x)sin⁡x dx\displaystyle\int e^x(\sin x + 2\cos x)\sin x\,dx

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  6. Question 6

    15 May 2026 S1

    80
    ∫ex(log⁡(sin⁡x)+1+cos⁡2x1−cos⁡2x)dx=…\int e^x \left(\log(\sin x) + \sqrt{\dfrac{1 + \cos 2x}{1 - \cos 2x}}\right) dx = \ldots

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