PYQ Vault

Integrand with sqrt(x) or sqrt(x - a): substitute x = t^2 (or x - a = t^2, x = t^6)

This type of question, asked 6 times: 10 May 2023 S1, 11 May 2024 S1, 23 Apr 2025 S1, 26 Apr 2025 S2, 15 Apr 2026 S1, 15 May 2026 S1. All 6 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    10 May 2023 S1

    131
    ∫xx+1 dx=\int\frac{\sqrt{x}}{x+1}\,dx=

    Tap an option to check your answer.

  2. Question 2

    11 May 2024 S1

    108
    Let f(x)=∫x(1+x)2 dx,  x≥0f(x) = \int \frac{\sqrt{x}}{(1+x)^2}\,dx,\; x \geq 0, then f(3)−f(1)f(3) - f(1) is equal to

    Tap an option to check your answer.

  3. Question 3

    23 Apr 2025 S1

    123
    ∫dxx+x=\int\frac{dx}{\sqrt{x}+x}=

    Tap an option to check your answer.

  4. Question 4

    26 Apr 2025 S2

    126
    ∫dxx12+x13=Ax12+Bx13+Cx16+Dlog(x16+1)+k\int\frac{dx}{x^{\frac{1}{2}}+x^{\frac{1}{3}}}= Ax^{\frac{1}{2}}+ Bx^{\frac{1}{3}}+ Cx^{\frac{1}{6}}+ Dlog\left( x^{\frac{1}{6}}+ 1 \right)+ k (where k is the integration constant) then values of A,B,CA,B,C and D are respectively,

    Tap an option to check your answer.

  5. Question 5

    15 Apr 2026 S1

    78
    ∫x−2x dx=\displaystyle\int\dfrac{\sqrt{x - 2}}{x}\,dx =

    Tap an option to check your answer.

  6. Question 6

    15 May 2026 S1

    81
    ∫xx5/2+4x3/2 dx=…\int \dfrac{x}{x^{5/2} + 4x^{3/2}}\, dx = \ldots

    Tap an option to check your answer.