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Derivative of tan^-1(f(x)) is a factor: substitute t = tan^-1(f(x))

This type of question, asked 3 times: 20 Apr 2025 S2, 25 Apr 2025 S2, 14 May 2026 S2. All 3 questions below, oldest first.

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  1. Question 1

    20 Apr 2025 S2

    110
    ∫etan⁡−12x1+4x2=\int\frac{e^{\tan^{- 1}2x}}{1 + 4x^{2}}=

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  2. Question 2

    25 Apr 2025 S2

    138
    ∫x4cos⁡(tan⁡−1x5)1+x10dx\int\frac{x^{4}\cos\left( \tan^{- 1}x^{5} \right)}{1 +x^{10}}dx equals

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  3. Question 3

    14 May 2026 S2

    82
    ∫x3sin⁡(tan⁡−1(x4))1+x8 dx=\displaystyle\int\dfrac{x^3\sin(\tan^{-1}(x^4))}{1 + x^8}\,dx =

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