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Two exponential integrals I and J: find I - J or J - I

This type of question, asked 2 times: 13 May 2024 S2, 12 May 2026 S1. All 2 questions below, oldest first.

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  1. Question 1

    13 May 2024 S2

    113
    If I=∫exe4x+e2x+1dxI=\int\frac{e^x}{e^{4x}+e^{2x}+1}dx and J=∫e−xe−4x+e−2x+1dxJ=\int\frac{e^{-x}}{e^{-4x}+e^{-2x}+1}dx, then for any arbitrary constant cc, that value of J−IJ-I equals

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  2. Question 2

    12 May 2026 S1

    78
    If I1=∫exe2x+ex+1 dxI_1 = \displaystyle\int\dfrac{e^x}{e^{2x} + e^x + 1}\,dx and I2=∫1e−2x+e−x+1 dxI_2 = \displaystyle\int\dfrac{1}{e^{-2x} + e^{-x} + 1}\,dx, then I1−I2=I_1 - I_2 =

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