Improper fraction over (x + 1)^2: divide, then partial fractions
This type of question, asked 3 times: 4 May 2023 S2, 21 Apr 2025 S2, 13 May 2026 S1. All 3 questions below, oldest first.
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Question 1
4 May 2023 S2
145∫(x+1)2x2+1dx=
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Question 2
21 Apr 2025 S2
144∫(x+1)2x3dx=
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Question 3
13 May 2026 S1
80The value of the integral ∫(x+1)2x2+1dx=…
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