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lim as x tends to 1 of (x^2 - ax + b)/(x - 1) is given: find a + b

The same question, asked 2 times: May 2022 S1*, 4 May 2023 S2. Every wording below, oldest first.

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  1. Question 1

    May 2022 S1

    134
    If lim⁡x→1x2−ax+bx−1=5\lim_{x \to 1} \frac{x^2 - ax + b}{x - 1} = 5, then (a+b)(a+b) is equal to

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  2. Question 2

    4 May 2023 S2

    132
    If lim⁡x→1x2−ax+bx−1=7\lim_{x\to1}\frac{x^2-ax+b}{x-1}=7, then a+ba+b is equal to

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