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(1 + cos(pi x))/(pi(1 - x)^2) continuous at x = 1: find f(1)

The same question, asked 2 times: 2 May 2023 S1, 15 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    2 May 2023 S1

    110
    If f(x)=1+cos⁡(πx)π(1−x)2f(x) = \dfrac{1 + \cos(\pi x)}{\pi(1-x)^2} for x≠1x \ne 1 is continuous at x=1x = 1, then f(1)f(1) is equal to

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  2. Question 2

    15 Apr 2026 S1

    69
    If the function f is continuous at x=1x = 1, where f(x)=1+cos⁡(πx)π(1−x)2f(x) = \dfrac{1 + \cos(\pi x)}{\pi(1 - x)^2}, for x≠1x \neq 1, then the value of f(1)f(1) is....

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