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(1 - tan x)/(4x - pi) continuous at pi/4: find f(pi/4)

The same question, asked 2 times: 3 May 2023 S1, 16 May 2023 S1. Every wording below, oldest first.

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  1. Question 1

    3 May 2023 S1

    103
    Let f(x)=1−tan⁡x4x−π, x≠π4, x∈ ⁣[0,π2]f(x)=\frac{1-\tan x}{4x-\pi},\ x\neq\frac{\pi}{4},\ x\in\!\left[0,\frac{\pi}{2}\right]. If f(x)f(x) is continuous in [0,π2]\left[0,\frac{\pi}{2}\right], then f ⁣(π4)f\!\left(\frac{\pi}{4}\right) is

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  2. Question 2

    16 May 2023 S1

    121
    Let f(x)=1−tan⁡x4x−π,  x≠π4,  x∈[0,π2)f(x) = \frac{1-\tan x}{4x-\pi},\; x \neq \frac{\pi}{4},\; x \in \left[0, \frac{\pi}{2}\right). f(x)f(x) is continuous in [0,π2)\left[0, \frac{\pi}{2}\right), then f ⁣(π4)f\!\left(\frac{\pi}{4}\right) is

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