Lines (x-1)/2 = (y+1)/3 = (z-1)/4 and (x-3)/1 = (y-k)/2 = z/1 intersect: find k
The same question, asked 7 times: 10 May 2023 S1*, 10 May 2023 S2*, 15 May 2023 S2*, 11 May 2024 S2*, 14 May 2024 S2*, 23 Apr 2025 S1*, 11 Apr 2026 S1. Every wording below, oldest first.
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Question 1
10 May 2023 S1
122
If the lines 2x−1=3y−2=4z−1 and −1x−3=2y−k=1z intersect, then k is equal to
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Question 2
10 May 2023 S2
126
If the line 2x−1=3y+1=4z−1 and 1x−3=2y−k=1z intersect, then the value of k is
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Question 3
15 May 2023 S2
127
If the lines 2x−1=3y+2=4z−1 and 1x−3=2y−k=1z intersect, then k has the value
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Question 4
11 May 2024 S2
104
If the lines 2x−1=3y+1=4z−1 and 1x−3=2y−k=1z intersect, then the value of k is:
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Question 5
14 May 2024 S2
137
If the lines 2x−k=3y+1=4z−1 and 1x−3=2y−9/2=1z intersect, then the value of k is
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Question 6
23 Apr 2025 S1
138
If the lines 2x−1=3y+1=4z−1 and 1x−3=2y−k=1z. intersect, then the value of k is
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Question 7
11 Apr 2026 S1
94
If the lines 2x−1=3y+1=4z−1 and 1x−2=2y+m=1z−2 intersect each other, then the value of m is....