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Plane through a point parallel to the lines (x-1)/3 = (y+2)/2 = z/-4 and x/2 = (y-1)/-3 = (z-2)/2

The same question, asked 3 times: 4 May 2023 S2*, 10 May 2023 S2, 16 May 2023 S2. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    4 May 2023 S2

    110
    The equation of the plane, passing through the point (−1,2,−3)(-1,2,-3) and parallel to the lines x−13=y−22=z−4\frac{x-1}{3}=\frac{y-2}{2}=\frac{z}{-4} and x2=y−1−3=z−22\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}, is

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  2. Question 2

    10 May 2023 S2

    134
    The equation of the plane through the point (2,−1,−3)(2,-1,-3) and parallel to the lines x−13=y+22=z−4\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4} and x2=y−1−3=z−22\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2} is

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  3. Question 3

    16 May 2023 S2

    139
    The equation of plane through the point (2,−1,−3)(2,-1,-3) and parallel to lines x−13=y+22=z−4\frac{x-1}{3} = \frac{y+2}{2} = \frac{z}{-4} and x2=y−1−3=z−22\frac{x}{2} = \frac{y-1}{-3} = \frac{z-2}{2} is

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