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Point of intersection of two lines

This type of question, asked 7 times: 10 May 2024 S2, 11 May 2024 S1, 20 Apr 2025 S2, 23 Apr 2025 S1, 11 Apr 2026 S2, 18 Apr 2026 S1, 14 May 2026 S2. All 7 questions below, oldest first.

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  1. Question 1

    10 May 2024 S2

    103
    Two lines x−31=y+13=z−6−1\frac{x-3}{1}=\frac{y+1}{3}=\frac{z-6}{-1} and x+57=y−2−6=z−34\frac{x+5}{7}=\frac{y-2}{-6}=\frac{z-3}{4} intersect at the point R. Then reflection of R in the xy-plane has co-ordinates

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  2. Question 2

    11 May 2024 S1

    133
    The lines x−13=y+12=z−15\frac{x-1}{3}=\frac{y+1}{2}=\frac{z-1}{5} and x+24=y−13=z+12\frac{x+2}{4}=\frac{y-1}{3}=\frac{z+1}{2}

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  3. Question 3

    20 Apr 2025 S2

    129
    The distance of the point (2,4,0)(2,4,0) from the point of intersection of the lines x+63=y2=z+11\frac{x+ 6}{3}=\frac{y}{2}=\frac{z+ 1}{1} and x−74=y−93=z−42\frac{x- 7}{4}=\frac{y- 9}{3}=\frac{z- 4}{2} is

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  4. Question 4

    23 Apr 2025 S1

    132
    The equation of the line passing through the point of intersection of x−12=y−23=z−34\frac{x- 1}{2}=\frac{y- 2}{3}=\frac{z- 3}{4} and x−45=y−12=z\frac{x- 4}{5}=\frac{y- 1}{2}=z and also through the point ( 2,1,−22,1, - 2 ) is

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  5. Question 5

    11 Apr 2026 S2

    93
    The point of intersection of the two lines x−33=y−3−1,z−1=0\dfrac{x - 3}{3} = \dfrac{y - 3}{-1}, z - 1 = 0 and x−62=z−13,y−2=0\dfrac{x - 6}{2} = \dfrac{z - 1}{3}, y - 2 = 0 is....

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  6. Question 6

    18 Apr 2026 S1

    95
    The coordinates of the point of intersection of the lines x−31=y−52=z−1−1\dfrac{x - 3}{1} = \dfrac{y - 5}{2} = \dfrac{z - 1}{-1} and x−42=y−2−1=z−42\dfrac{x - 4}{2} = \dfrac{y - 2}{-1} = \dfrac{z - 4}{2} are...

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  7. Question 7

    14 May 2026 S2

    92
    The equation of the line passing through the point of intersection of the lines x−31=y−52=z−1−1\dfrac{x - 3}{1} = \dfrac{y - 5}{2} = \dfrac{z - 1}{-1} & x−42=y−2−1=z−42\dfrac{x - 4}{2} = \dfrac{y - 2}{-1} = \dfrac{z - 4}{2} and in the direction of i^−2j^+k^\hat{i} - 2\hat{j} + \hat{k} is

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