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Equation of the line through a point perpendicular to two given lines or vectors

This type of question, asked 6 times: 2 May 2023 S1, 2 May 2023 S2, 11 May 2023 S1, 11 May 2024 S2, 12 May 2026 S2, 13 May 2026 S2. All 6 questions below, oldest first.

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  1. Question 1

    2 May 2023 S1

    136
    The equation of the line passing through the point (−1,3,−2)(-1, 3, -2) and perpendicular to each of the lines x1=y2=z3\dfrac{x}{1} = \dfrac{y}{2} = \dfrac{z}{3} and x+2−3=y−12=z+15\dfrac{x+2}{-3} = \dfrac{y-1}{2} = \dfrac{z+1}{5}, is

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  2. Question 2

    2 May 2023 S2

    140
    The equation of the line through A(1,2,3)A(1,2,3) and perpendicular to the vectors 2i^+j^−k^2\hat{i}+\hat{j}-\hat{k} and i^+3j^+2k^\hat{i}+3\hat{j}+2\hat{k} is

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  3. Question 3

    11 May 2023 S1

    130
    The equation of the line passing through the point (3,1,2) and perpendicular to the lines x−11=y−22=z−33\frac{x-1}{1}=\frac{y-2}{2}=\frac{z-3}{3} and x−3=y2=z5\frac{x}{-3}=\frac{y}{2}=\frac{z}{5} is

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  4. Question 4

    11 May 2024 S2

    131
    The equation of line passing through the point (1,2,3)(1,2,3) and perpendicular to the lines x−23=y−12=z+1−2\frac{x-2}{3}=\frac{y-1}{2}=\frac{z+1}{-2} and x2=y−3=z1\frac{x}{2}=\frac{y}{-3}=\frac{z}{1} is:

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  5. Question 5

    12 May 2026 S2

    93
    The vector equation of the line passing through the point (1,2,−4)(1, 2, -4) and perpendicular to the two the lines x−83=y+19−16=z−107\dfrac{x - 8}{3} = \dfrac{y + 19}{-16} = \dfrac{z - 10}{7} and x−53=y−338=5−z5\dfrac{x - 5}{3} = \dfrac{y - 33}{8} = \dfrac{5 - z}{5} is...

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  6. Question 6

    13 May 2026 S2

    89
    The cartesian equation of the line passing through the point i^+2j^+3k^\hat{i} + 2\hat{j} + 3\hat{k} and perpendicular to the vectors i^+j^+k^\hat{i} + \hat{j} + \hat{k} and 2i^−j^+k^2\hat{i} - \hat{j} + \hat{k} is

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