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Area of the triangle a plane cuts from the coordinate axes

This type of question, asked 5 times: 20 Apr 2025 S1, 25 Apr 2025 S2, 26 Apr 2025 S1, 13 Apr 2026 S1, 19 Apr 2026 S1. All 5 questions below, oldest first.

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  1. Question 1

    20 Apr 2025 S1

    139
    If the plane x3+y2−z4=1\frac{x}{3}+\frac{y}{2}-\frac{z}{4}= 1 cuts the co-ordinate axes at points A,BA,B and C , then the area of the triangle ABC is

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  2. Question 2

    25 Apr 2025 S2

    110
    If the plane x2−y3−z5=1\frac{x}{2}-\frac{y}{3}-\frac{z}{5}= 1 cuts the co-ordinate axes in points A,B,CA,B,C respectively, then the area of the triangle ABCABC is

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  3. Question 3

    26 Apr 2025 S1

    144
    If the plane x2+y3+z6=1\frac{x}{2}+\frac{y}{3}+\frac{z}{6}= 1 cuts the co-ordinate axes at points A,B,CA,B,C respectively, then area of the triangle ABC is

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  4. Question 4

    13 Apr 2026 S1

    95
    The plane x2+y3+z4=1\dfrac{x}{2} + \dfrac{y}{3} + \dfrac{z}{4} = 1 cuts the co-ordinate axes at the points A, B, C respectively. Then the area of triangle ABC is

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  5. Question 5

    19 Apr 2026 S1

    93
    The plane x2+y3+z4=1\dfrac{x}{2} + \dfrac{y}{3} + \dfrac{z}{4} = 1 cuts the axes at the points A, B, C then the area of triangle ABC is

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