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(p and q) implies (r or not s) is false: truth values of p, q, r, s

The same question, asked 2 times: 21 Apr 2025 S1, 13 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    21 Apr 2025 S1

    142
    If the statement pattern (p∧q)→(r∨∼s)(p\land q) \rightarrow (r\vee \sim s) is false, then the truth values of p,q,rp,q,r and ss are respectively

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  2. Question 2

    13 Apr 2026 S1

    62
    The statement pattern (p∧q)→(r∨∼s)(p \wedge q) \to (r \vee \sim s) is false. Then the truth values of p,q,rp, q, r and ss are respectively

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