PYQ Vault
EbooksTutor

[(p and not q) and (p and r)] implies (not p or q) is false: truth values of p, q, r

The same question, asked 2 times: 4 May 2023 S1, 21 Apr 2025 S2. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    4 May 2023 S1

    149
    If (p∧∼q)∧(p∧r)→∼p∨q(p\wedge\sim q)\wedge(p\wedge r)\to\sim p\vee q is false, then the truth values of pp, qq and rr are respectively

    Tap an option to check your answer.

  2. Question 2

    21 Apr 2025 S2

    131
    If [(p∧∼q)∧(p∧r)]→(∼p∨q)[(p\land \sim q) \land (p\land r)] \to (\sim p\vee q) has truth value false then truth values of the statements p,q,rp,q,r are respectively

    Tap an option to check your answer.