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Truth values of p, q, r when a given compound statement is false

This type of question, asked 14 times: 2 May 2023 S1, 4 May 2023 S1, 9 May 2023 S1, 9 May 2023 S2, 10 May 2023 S2, 15 May 2023 S1, 11 May 2024 S2, 21 Apr 2025 S1, 21 Apr 2025 S2, 26 Apr 2025 S1, 13 Apr 2026 S1, 19 Apr 2026 S2, 14 May 2026 S1, 15 May 2026 S1. All 14 questions below, oldest first.

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  1. Question 1

    2 May 2023 S1

    129
    If the statement p∨∼(q∧r)p \vee \sim(q \wedge r) is false, then the truth values of pp, qq and rr are respectively

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  2. Question 2

    4 May 2023 S1

    149
    If (p∧∼q)∧(p∧r)→∼p∨q(p\wedge\sim q)\wedge(p\wedge r)\to\sim p\vee q is false, then the truth values of pp, qq and rr are respectively

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  3. Question 3

    9 May 2023 S1

    149
    Let pp, qq, rr be three statements such that the truth value of (p∧q)→(∼q∨r)(p\wedge q)\to(\sim q\vee r) is F. Then the truth values of pp, qq, rr are respectively

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  4. Question 4

    9 May 2023 S2

    103
    If p→(∼p∨∼q)p \to (\sim p \vee \sim q) is false, then the truth values of pp and qq are respectively

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  5. Question 5

    10 May 2023 S2

    150
    If (p∧∼r)→(∼p∨q)(p\wedge\sim r)\rightarrow(\sim p\vee q) has truth value False, then truth values of p, q, r are respectively.

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  6. Question 6

    15 May 2023 S1

    123
    If p→(q∨r)p\to(q\vee r) is false, then the truth values of p,q,rp, q, r are respectively

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  7. Question 7

    11 May 2024 S2

    127
    If truth value of logical statement (p↔∼q)→(∼p∧q)(p\leftrightarrow\sim q)\to(\sim p\wedge q) is false, then the truth values of p and q are respectively

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  8. Question 8

    21 Apr 2025 S1

    142
    If the statement pattern (p∧q)→(r∨∼s)(p\land q) \rightarrow (r\vee \sim s) is false, then the truth values of p,q,rp,q,r and ss are respectively

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  9. Question 9

    21 Apr 2025 S2

    131
    If [(p∧∼q)∧(p∧r)]→(∼p∨q)[(p\land \sim q) \land (p\land r)] \to (\sim p\vee q) has truth value false then truth values of the statements p,q,rp,q,r are respectively

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  10. Question 10

    26 Apr 2025 S1

    118
    If the truth value of the expression [(p∨q)∧(q→r)∧(∼r)]→(p∧q)\lbrack(p\vee q) \land (q\rightarrow r) \land ( \sim r)\rbrack \rightarrow (p\land q) is False, then truth values of p,q,rp,q,r are respectively.

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  11. Question 11

    13 Apr 2026 S1

    62
    The statement pattern (p∧q)→(r∨∼s)(p \wedge q) \to (r \vee \sim s) is false. Then the truth values of p,q,rp, q, r and ss are respectively

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  12. Question 12

    19 Apr 2026 S2

    62
    If ∼p→q\sim p \to q is false and q↔rq \leftrightarrow r is false, then the truth value of (p,q,r)(p, q, r) is...

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  13. Question 13

    14 May 2026 S1

    65
    If p∧qp \wedge q is F and p→qp \to q is F, then the truth values of pp and qq respectively are

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  14. Question 14

    15 May 2026 S1

    63
    If p→(∼p∨q)p \rightarrow (\sim p \vee q) is false, then the truth values of p,qp, q are:

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