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Given that a compound statement is false or true, find the truth value of other statements

This type of question, asked 14 times: 16 May 2023 S2, 13 May 2024 S2, 14 May 2024 S2, 20 Apr 2025 S1, 22 Apr 2025 S1, 11 Apr 2026 S1, 13 Apr 2026 S2, 16 Apr 2026 S2, 17 Apr 2026 S1, 18 Apr 2026 S2, 19 Apr 2026 S2, 20 Apr 2026 S2, 13 May 2026 S1, 15 May 2026 S2. All 14 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    16 May 2023 S2

    110
    Truth values of p→rp \to r is F and p↔qp \leftrightarrow q is F. Then the truth values of (∼p∨q)→(p∨∼q)(\sim p \vee q) \to (p \vee \sim q) and (p∧∼q)→(∼p∧q)(p \wedge \sim q) \to (\sim p \wedge q) are respectively

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  2. Question 2

    13 May 2024 S2

    106
    If qq is false and (p∧q)↔r(p\wedge q)\leftrightarrow r is true, then ………. is a tautology.

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  3. Question 3

    14 May 2024 S2

    125
    If the statement p↔(q→p)p \leftrightarrow (q \to p) is false, then true statement/statement pattern is

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  4. Question 4

    20 Apr 2025 S1

    117
    If a statement qq has truth value False and (p∧q)↔r(p\land q) \leftrightarrow r has truth value True then which of the following has truth value true?

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  5. Question 5

    22 Apr 2025 S1

    106
    If the truth value of the statement pattern [p∧∼r]→∼r∧q\lbrack p \land \sim r\rbrack \rightarrow \sim r \land q is False, then which of the following has truth value False?

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  6. Question 6

    11 Apr 2026 S1

    60
    If the truth value of the compound statement [(p∨q)∧(q→r)∧(∼r)]→(p∧q)[(p \vee q) \wedge (q \to r) \wedge (\sim r)] \to (p \wedge q) is False then the truth values of p→qp \to q and q→pq \to p are respectively......

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  7. Question 7

    13 Apr 2026 S2

    62
    If the truth value of the compound statement [(p∨q)∧(q→r)∧(∼r)]→(p∧q)[(p \vee q) \wedge (q \to r) \wedge (\sim r)] \to (p \wedge q) is false, then the truth values of p→qp \to q and q→pq \to p are respectively...

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  8. Question 8

    16 Apr 2026 S2

    60
    If the truth value of the compound statement [(p↔q)∧(q→r)∧∼r]→(p∧∼q)[(p \leftrightarrow q) \wedge (q \to r) \wedge \sim r] \to (p \wedge \sim q) is false, then the truth values of the statement patterns (p→q)↔(q→r)(p \to q) \leftrightarrow (q \to r) and ∼(p∨r)→(q∧p)\sim(p \vee r) \to (q \wedge p) are, respectively ...

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  9. Question 9

    17 Apr 2026 S1

    62
    If p→(q∨∼r)p \to (q \vee \sim r) is false, then the truth values of (p↔q)∧r(p \leftrightarrow q) \wedge r and ∼p→∼q\sim p \to \sim q are :

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  10. Question 10

    18 Apr 2026 S2

    60
    If the truth value of the statement pattern (∼p∧q)∨(∼p∧∼q)∨(p∧∼q)(\sim p \wedge q) \vee (\sim p \wedge \sim q) \vee (p \wedge \sim q) is FF, then the truth values of (p∨∼q)(p \vee \sim q) and (p→q)(p \to q) are …\ldots respectively.

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  11. Question 11

    19 Apr 2026 S2

    60
    If the truth value of [(p∨q)∧(q→r)∧(∼r)]→(p∧q)[(p \vee q) \wedge (q \to r) \wedge (\sim r)] \to (p \wedge q) is false, then which of the following is NOT true?

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  12. Question 12

    20 Apr 2026 S2

    60
    If ∼p∨q\sim p \vee q is false then which of the following is correct?

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  13. Question 13

    13 May 2026 S1

    65
    If the statement pattern (p∨∼q)∧(∼p∨q)(p \vee \sim q) \wedge (\sim p \vee q) is true, then which of the following is true?

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  14. Question 14

    15 May 2026 S2

    68
    If the compound statement (p∧∼q)→(q∨∼r)(p \wedge \sim q) \rightarrow (q \vee \sim r) is false then which of the following statements is a true ?

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