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Tangent to a square-root curve at the point where its x and y coordinates are equal

The same question, asked 2 times: 11 May 2024 S2*, 17 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    11 May 2024 S2

    148
    The equation of the tangent to the curve y=9−2x2y=\sqrt{9-2x^2}, at the point where the ordinate and abscissa are equal, is

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  2. Question 2

    17 Apr 2026 S2

    75
    The equation of the tangent to the curve y=9−3x2y = \sqrt{9 - 3x^2} at the point where the ordinate and abscissa equal is...

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