Converse, inverse or contrapositive of a symbolic statement pattern

1. A.
   $\sim r\rightarrow(\sim p\vee q)$
2. B.
   $r\rightarrow(\sim p\wedge\sim q)$
3. C.
   $(\sim p\vee q)\rightarrow\sim r$
4. D.
   $r\rightarrow(p\wedge q)$

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1. A.
   $p\to(q\to r)$
2. B.
   $(q\to r)\to\sim p$
3. C.
   $(p\lor q)\to r$
4. D.
   $(q\to r)\to p$

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1. A.
   $(\sim p \wedge q) \to p$
2. B.
   $(\sim p \vee q) \to p$
3. C.
   $p \to (\sim p \vee q)$
4. D.
   $(p \vee q) \to p$

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1. A.
   $p \rightarrow q \land r$
2. B.
   $(q \land r) \rightarrow p$
3. C.
   $\sim q \vee \sim r \rightarrow p$
4. D.
   $(r \vee \sim q) \rightarrow \sim p$

Tap an option to check your answer.

1. A.
   $\sim[p \vee (r \to q)]$
2. B.
   $p \vee (r \to q)$
3. C.
   $\sim[p \vee (q \to r)]$
4. D.
   $p \vee (q \to r)$

Tap an option to check your answer.

1. A.
   $(p \wedge \sim q) \to [p \wedge (p \to q)]$
2. B.
   $(\sim p \wedge \sim q) \to [\sim p \wedge (p \to \sim q)]$
3. C.
   $(\sim p \vee q) \wedge [\sim p \vee (p \wedge \sim q)]$
4. D.
   $(\sim p \vee q) \to [\sim p \wedge (p \wedge \sim q)]$

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1. A.
   $p \to q$
2. B.
   $p \wedge q$
3. C.
   $p \vee q$
4. D.
   $\sim p \to \sim q$

Tap an option to check your answer.

1. A.
   $(p \vee q) \vee \sim r$
2. B.
   $(p \vee q) \vee r$
3. C.
   $(p \vee q) \to \sim r$
4. D.
   $(p \wedge q) \vee \sim r$

Tap an option to check your answer.