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Mean and variance of 50 observations are 16 and 256: find the mean of (x - 5)^2

The same question, asked 2 times: 11 May 2024 S2, 14 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    11 May 2024 S2

    126
    If both mean and variance of 50 observations x1,x2,…,x50x_1, x_2,\ldots,x_{50} are equal to 16 and 256 respectively, then mean of (x1−5)2,(x2−5)2,…,(x50−5)2(x_1-5)^2,(x_2-5)^2,\ldots,(x_{50}-5)^2 is

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  2. Question 2

    14 May 2024 S2

    149
    If both mean and variance of 50 observations x1,x2,…,x50x_1, x_2, \ldots, x_{50} are equal to 16 and 256 respectively, then mean of (x1−5)2,(x2−5)2,…,(x50−5)2(x_1-5)^2, (x_2-5)^2, \ldots, (x_{50}-5)^2 is

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