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Table of P(X): P(E or F) where E = X is prime and F = X less than a number

The same question, asked 6 times: 10 May 2023 S1*, 11 May 2023 S2*, 13 May 2024 S2*, 13 Apr 2026 S1*, 15 Apr 2026 S2*, 16 Apr 2026 S1. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    10 May 2023 S1

    137
    A random variable X has the following probability distribution: | X | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | | P(X=x) | 0.15 | 0.23 | 0.12 | 0.10 | 0.20 | 0.08 | 0.07 | 0.05 | For the events E={X is prime number}E=\{X \text{ is prime number}\}, F={X<4}F=\{X<4\}. Then P(E∪F)=P(E \cup F)=

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  2. Question 2

    11 May 2023 S2

    102
    A random variable X has the following probability distribution: X=x: 1,2,3,4,5,6,7,8 with P(X=x): 0.15,0.23,0.10,0.12,0.20,0.08,0.07,0.05. For the event E={X is a prime number}E=\{X \text{ is a prime number}\}, F={X<4}F=\{X<4\}, then P(E∪F)P(E \cup F) is

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  3. Question 3

    13 May 2024 S2

    118
    A random variable X has the probability distribution.
    X=xP(X=x)
    10.15
    20.23
    30.12
    40.20
    50.08
    60.10
    70.05
    80.07
    for the events E={X is a prime number}E=\{X\text{ is a prime number}\} and F={x<5}F=\{x<5\}, P(E∪F)P(E\cup F) is

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  4. Question 4

    13 Apr 2026 S1

    98
    A random variable X has the following probability distribution
    X=xX = x1122334455667788
    P(X=x)P(X = x)0.150.150.230.230.100.100.120.120.200.200.080.080.070.070.050.05
    For the events E={XE = \{X is a prime number}\}, F={X<4}F = \{X < 4\}, P(E∪F)P(E \cup F) is

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  5. Question 5

    15 Apr 2026 S2

    99
    A random variable X has the following probability distribution
    X12345678
    P(X=xx)0.150.230.120.100.200.080.070.05
    For the event E = { X is a prime number } and F = { X < 4 }, P(E∪\cupF) =

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  6. Question 6

    16 Apr 2026 S1

    98
    A random variable X has the probability distribution
    X=xX = x12345678
    P(X=x)P(X = x)0.230.150.120.100.200.070.080.05
    for the events E = {X is a prime number} and F = {X ≤\le 3}, then P (E∪\cupF)=

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