PYQ Vault

Probabilities from a cumulative distribution (c.d.f.) table

This type of question, asked 2 times: 21 Apr 2025 S2, 26 Apr 2025 S1. All 2 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    21 Apr 2025 S2

    120
    The c.d.f. of a discrete random variable XX is
    XXF(X=x)F(X = x)
    −3-30.1
    −1-10.3
    00.5
    10.65
    30.75
    50.85
    70.90
    91
    Then P[X=−3]P[X<0]=\frac{P\lbrack X = - 3\rbrack}{P\lbrack X < 0\rbrack}=

    Tap an option to check your answer.

  2. Question 2

    26 Apr 2025 S1

    131
    The cumulative distribution function of a discrete random variable X is then P(X⩽0)P(X>0)=\frac{P(X \leqslant 0)}{P(X > 0)}=
    X=xX = xF(X=x)F(X = x)
    −4-40.1
    −2-20.3
    00.5
    20.65
    40.75
    60.85
    80.90
    101

    Tap an option to check your answer.