Probability distribution of the number of defective items drawn without replacement

1. A.
   $\begin{array}{c|cccc} X & 0 & 1 & 2 & 3 \\ \hline P(X = x) & \frac{28}{57} & \frac{8}{95} & \frac{8}{19} & \frac{1}{285} \end{array}$
2. B.
   $\begin{array}{c|cccc} X & 0 & 1 & 2 & 3 \\ \hline P(X = x) & \frac{28}{57} & \frac{8}{19} & \frac{8}{95} & \frac{1}{285} \end{array}$
3. C.
   $\begin{array}{c|cccc} X & 0 & 1 & 2 & 3 \\ \hline P(X = x) & \frac{28}{57} & \frac{8}{95} & \frac{1}{285} & \frac{8}{19} \end{array}$
4. D.
   $\begin{array}{c|cccc} X & 0 & 1 & 2 & 3 \\ \hline P(X = x) & \frac{1}{285} & \frac{8}{95} & \frac{8}{19} & \frac{28}{57} \end{array}$

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1. A.
   $X = 0, 1, 2;\ P(X) = \dfrac{10}{28}, \dfrac{15}{28}, \dfrac{3}{28}$
2. B.
   $X = 1, 2, 3;\ P(X) = \dfrac{10}{28}, \dfrac{15}{28}, \dfrac{3}{28}$
3. C.
   $X = 0, 1, 2;\ P(X) = \dfrac{15}{28}, \dfrac{10}{28}, \dfrac{3}{28}$
4. D.
   $X = 1, 2, 3;\ P(X) = \dfrac{15}{28}, \dfrac{10}{28}, \dfrac{3}{28}$

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