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A = 30 degrees: value of (1 + a/c + b/c)(1 + c/b - a/b)

The same question, asked 2 times: 21 Apr 2025 S1, 26 Apr 2025 S2. Every wording below, oldest first.

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  1. Question 1

    21 Apr 2025 S1

    124
    With usual notation, in triangle ABC , m∠A=30∘m\angle A =30^{\circ} then the value of (1+ac+bc)(1+cb−ab)\left( 1 +\frac{a}{c}+\frac{b}{c} \right)\left( 1 +\frac{c}{b}-\frac{a}{b} \right) is equal to

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  2. Question 2

    26 Apr 2025 S2

    112
    In a triangle ABC with usual notations if ∠A=30∘\angle A =30^{\circ}, then the value of (1+ac+bc)(1+cb−ab)=\left( 1 +\frac{a}{c}+\frac{b}{c} \right)\left( 1 +\frac{c}{b}-\frac{a}{b} \right)=

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