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Angles in A.P. and b:c = sqrt3:sqrt2: find angle A

The same question, asked 3 times: 11 May 2023 S1, 11 Apr 2026 S2, 20 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    11 May 2023 S1

    133
    If in a triangle ABC, with usual notations, the angles are in A.P. and b:c=3:2b:c = \sqrt{3}:\sqrt{2}, then angle A =

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  2. Question 2

    11 Apr 2026 S2

    64
    In triangle ABC, with usual notations, if the angles are in Arithmetic Progression and 3c2=2b23c^2 = 2b^2, then the measure of angle A is

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  3. Question 3

    20 Apr 2026 S2

    62
    The angles of △ABC\triangle ABC are in A.P. and b:c=3:2b : c = \sqrt{3} : \sqrt{2} then ∠A=\angle A =

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