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Value of cos^2 48 - sin^2 12 degrees using sin 18 degrees

The same question, asked 2 times: 9 May 2024 S1, 12 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    9 May 2024 S1

    109
    If sin⁡18∘=5−14\sin18^\circ=\frac{\sqrt{5}-1}{4}, then cos⁡248∘−sin⁡212∘\cos^248^\circ-\sin^212^\circ has the value

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  2. Question 2

    12 May 2024 S2

    110
    cos⁡248°−sin⁡212°=\cos^2 48° - \sin^2 12° = ……. if sin⁡18°=5−14\sin 18° = \frac{\sqrt{5}-1}{4}

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