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Area of the smaller part of a circle cut off by a vertical line

The same question, asked 3 times: 12 May 2024 S2*, 26 Apr 2025 S1, 15 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    12 May 2024 S2

    104
    The area (in sq. units) of the smaller part of the circle x2+y2=a2x^2 + y^2 = a^2 cut off by the line x=a2x = \frac{a}{\sqrt{2}} is

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  2. Question 2

    26 Apr 2025 S1

    115
    The area of smaller part between the circle x2+y2=4x^{2}+y^{2}= 4 and the line x=1x= 1 is ____\_\_\_\_ sq.units.

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  3. Question 3

    15 Apr 2026 S1

    83
    The area of the smaller region bounded by the circle x2+y2=4x^2 + y^2 = 4 and the line x=1x = 1 is...

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