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Intensity at a point in Young's experiment from the path or phase difference

This type of question, asked 17 times: 3 May 2023 S2, 9 May 2023 S2, 15 May 2023 S1, 15 May 2023 S2, 16 May 2023 S1, 9 May 2024 S2, 10 May 2024 S2, 12 May 2024 S1, 12 May 2024 S2, 19 Apr 2025 S2, 25 Apr 2025 S2, 11 Apr 2026 S1, 16 Apr 2026 S1, 19 Apr 2026 S1, 19 Apr 2026 S2, 13 May 2026 S1, 15 May 2026 S2. All 19 questions below, oldest first.

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  1. Question 1

    3 May 2023 S2

    47
    In Young's double slit experiment using monochromatic light of wavelength 'λ\lambda', the intensity of light at a point on the screen where path difference 'λ\lambda' is K units. The intensity of light at a point where the path difference is λ6\frac{\lambda}{6} is
    cos⁡π6=sin⁡π3=32\cos\frac{\pi}{6}=\sin\frac{\pi}{3}=\frac{\sqrt{3}}{2}

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  2. Question 2

    9 May 2023 S2

    36
    In Young's double slit experiment using monochromatic light of wavelength 'λ\lambda', the maximum intensity of light at a point on the screen is 'K' units. The intensity of light at a point where the path difference is 'λ6\frac{\lambda}{6}', is cos⁡60∘=sin⁡30∘=0.5,sin⁡60∘=cos⁡30∘=32\cos 60^\circ = \sin 30^\circ = 0.5, \sin 60^\circ = \cos 30^\circ = \frac{\sqrt{3}}{2}

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  3. Question 3

    9 May 2023 S2

    10
    In the Young's double slit experiment, the intensity at a point on the screen, where the path difference is λ\lambda (λ\lambda = wavelength) is β\beta. The intensity at a point where the path difference is λ3\frac{\lambda}{3}, will be cos⁡π3=12\cos\frac{\pi}{3} = \frac{1}{2}

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  4. Question 4

    15 May 2023 S1

    26
    In Young's double slit experiment, II is the minimum intensity and I1I_{1} is the intensity at a point where the path difference is λ4\frac{\lambda}{4} where λ\lambda is the wavelength of light used. The ratio I/I1I/I_{1} is (Intensities of the two interfering waves are same) cos⁡0∘=1,cos⁡90∘=0\cos 0^{\circ}=1, \cos 90^{\circ}=0

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  5. Question 5

    15 May 2023 S2

    44
    In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is λ\lambda is xx units, λ\lambda being the wavelength of light used. The intensity at a point where the path difference is λ/4\lambda/4 will be (cos⁡2π=1, cos⁡π2=0\cos 2\pi = 1,\, \cos \frac{\pi}{2} = 0)

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  6. Question 6

    16 May 2023 S1

    25
    In Young's double slit experiment, intensity at a point is 14\frac{1}{4} of the maximum intensity. The angular position of this point is

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  7. Question 7

    9 May 2024 S2

    3
    In Young's double slit experiment, the wavelength of light used is λ\lambda. The intensity at a point is II where path difference is λ4\frac{\lambda}{4}. If I0I_0 denotes the maximum intensity, then the ratio II0\frac{I}{I_0} is (sin⁡π4=cos⁡π4=12)\left(\sin\frac{\pi}{4} = \cos\frac{\pi}{4} = \frac{1}{\sqrt{2}}\right)

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  8. Question 8

    10 May 2024 S2

    10
    Light waves from two coherent sources arrive at two points on a screen with path difference of zero and 'λ2\frac{\lambda}{2}'. The ratio of intensities at the points is [cos⁡0∘=1,  cos⁡π=−1][\cos 0^\circ=1,\;\cos\pi=-1]

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  9. Question 9

    12 May 2024 S1

    5
    In Young's double slit experiment the intensities at two points, for the path difference λ4\frac{\lambda}{4} and λ3\frac{\lambda}{3} (λ=\lambda = wavelength of light used) are I1I_{1} and I2I_{2} respectively. If I0I_{0} denotes the intensity produced by each one of the individual slits then I1+I2I0\frac{I_{1}+I_{2}}{I_{0}} is equal to (cos⁡60∘=0.5,cos⁡45∘=12)(\cos 60^{\circ}=0.5,\cos 45^{\circ}=\frac{1}{\sqrt{2}})

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  10. Question 10

    12 May 2024 S2

    39
    The ratio of the intensities at two points on a screen in Young's double slit experiment, where the waves from the two slits have a path difference of λ4\frac{\lambda}{4} and λ6\frac{\lambda}{6}, is [cos⁡90∘=0\cos 90^\circ = 0, cos⁡60∘=0.5\cos 60^\circ = 0.5]

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  11. Question 11

    19 Apr 2025 S2

    21
    In Young's double slit experiment, the intensity on screen at a point where path difference is λ4\frac{\lambda}{4} is K2\frac{K}{2}. The intensity at a point when path difference is ' λ\lambda ' will be

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  12. Question 12

    25 Apr 2025 S2

    5
    In Young's double slit experiment, at two points PP and QQ on screen, waves from slits S1S_{1} and S2S_{2} have a path difference of 0 and λ4\frac{\lambda}{4} respectively. The ratio of intensities at point PP to that at QQ will be (cos⁡0∘=1,cos⁡45∘=12)\left( \cos0^{\circ}= 1,\cos45^{\circ}=\frac{1}{\sqrt{2}} \right)

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  13. Question 13

    11 Apr 2026 S1

    142
    In a Young's double slit experiment, the intensities at two points, for the path difference λ4\dfrac{\lambda}{4} and λ3\dfrac{\lambda}{3} (λ\lambda being the wavelength of light used) are I1I_1 and I2I_2 respectively. If I0I_0 denotes the intensity produced by each one of the individual slits, then I1+I2I0=\dfrac{I_1 + I_2}{I_0} = (cos⁡45∘=12,cos⁡60=12)\left(\cos 45^\circ = \dfrac{1}{\sqrt{2}}, \cos 60 = \dfrac{1}{2}\right)

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  14. Question 14

    16 Apr 2026 S1

    142
    The ratio of intensities at two points on the screen in Young's double slit experiment when waves from the two slits have a path difference of zero and λ/4\lambda/4 is (λ\lambda is the wavelength of light used) (cos⁡0∘=1,cos⁡π/2=0)(\cos 0^\circ = 1, \cos\pi/2 = 0)

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  15. Question 15

    19 Apr 2026 S1

    141
    In Young's double slit experiment, the wavelength of light used is λ\lambda. The intensity on the screen at a point for path difference 'λ\lambda' is 'XX'. The intensity at the point for path difference (λ6)\left(\dfrac{\lambda}{6}\right) is (cos⁡180∘=−1,cos⁡30∘=32)\left(\cos 180^\circ = -1, \cos 30^\circ = \dfrac{\sqrt{3}}{2}\right)

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  16. Question 16

    19 Apr 2026 S2

    142
    In biprism experiment, the maximum intensity is I0I_0. If the path difference between the two interfering waves is λ3\dfrac{\lambda}{3}, then intensity at the point on the screen is [sin⁡30∘=cos⁡60∘=0.5,sin⁡60∘=cos⁡30∘=3/2][\sin 30^\circ = \cos 60^\circ = 0.5, \sin 60^\circ = \cos 30^\circ = \sqrt{3}/2]

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  17. Question 17

    13 May 2026 S1

    142
    The ratio of intensity at the centre of a bright fringe to the intensity at a point distant (14)th\left(\dfrac{1}{4}\right)^{th} of the distance between two successive bright fringes will be (cos⁡0∘=1,cos⁡90∘=0)(\cos 0^\circ = 1, \cos 90^\circ = 0)

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  18. Question 18

    13 May 2026 S1

    143
    The wavelength of light used in Young's double slit experiment, is λ\lambda. The intensity at a point on the screen is I, where the path difference is λ6\dfrac{\lambda}{6}. If I0I_0 is the maximum intensity then the ratio I to I0I_0 is (cos⁡30∘=32)\left(\cos 30^\circ = \dfrac{\sqrt{3}}{2}\right)

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  19. Question 19

    15 May 2026 S2

    142
    At two points PP and QQ on the screen in Young's double slit experiment, waves from slits S1S_1 and S2S_2 have a path difference of zero and λ4\dfrac{\lambda}{4} respectively. The ratio of intensities at PP and QQ will be (cos⁡0∘=1, cos⁡45∘=12)\left(\cos 0^\circ = 1,\ \cos 45^\circ = \dfrac{1}{\sqrt{2}}\right)

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