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De Broglie wavelength increases when the accelerating potential changes from V1 to V2: find V1/V2

The same question, asked 2 times: 10 May 2024 S1*, 13 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    10 May 2024 S1

    21
    An electron accelerated through potential V1V_1 has de Broglie wavelength λ\lambda. When potential changes to V2V_2 wavelength increases by 50%. The value of V1V2\frac{V_1}{V_2} is

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  2. Question 2

    13 Apr 2026 S2

    145
    An electron accelerated through a potential difference V1V_1 has a de-Broglie wavelength of λ\lambda. When the potential is changed to V2V_2, its de-Broglie wavelength increases to 2λ2\lambda. The value of (V1/V2)(V_1/V_2) is equal to

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