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Force of a light beam on a surface that absorbs part of it and reflects the rest

The same question, asked 2 times: 20 Apr 2025 S1*, 13 May 2026 S1. Every wording below, oldest first.

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  1. Question 1

    20 Apr 2025 S1

    20
    A parallel beam of light is incident normally on a plane surface absorbing 50%50\% of the light and reflecting the rest. If the incident beam carries 90 W of power, the force exerted by it on the surface is ( C=C = velocity of light in air =3×108 m/s= 3 \times10^{8}\text{ }m/s )

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  2. Question 2

    13 May 2026 S1

    144
    A parallel beam of light is incident normally on a plane surface absorbing 40%40\% of light and reflecting the rest. If the incident beam carries 6060 W of power the force exerted by it on the surface is (C = velocity of light = 3×1083 \times 10^8 m/s )

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