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LCR circuit: removing L or C gives a phase difference of pi/3 each time: power factor of the circuit

The same question, asked 4 times: 21 Apr 2025 S2, 25 Apr 2025 S1, 17 Apr 2026 S1, 13 May 2026 S1. Every wording below, oldest first.

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  1. Question 1

    21 Apr 2025 S2

    37
    In an electrical circuit ' RR ', ' LL ', ' CC ' and an a.c. voltage source are all connected in series. When ' LL ' is removed from the circuit, the phase difference between the voltage and the current in the circuit is π3\frac{\pi}{3}. If instead ' CC ' is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is (tan⁡π3=3)\left( \tan\frac{\pi}{3}=\sqrt{3} \right)

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  2. Question 2

    25 Apr 2025 S1

    45
    In LCR series circuit, when ' LL ' is removed from the circuit, the phase difference between voltage and current in the circuit is π3\frac{\pi}{3}. If ' CC ' is removed from the circuit instead of LL then phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is (tan⁡60∘=3)\left( \tan60^{\circ}=\sqrt{3} \right)

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  3. Question 3

    17 Apr 2026 S1

    135
    The resistor 'RR' inductance 'LL' and capacitance 'CC' are connected in series with an a.c. source. When 'LL' is removed from the circuit, the phase difference between voltage and current in the circuit is π3\dfrac{\pi}{3}. If instead, C is removed from the circuit, the phase difference is again π3\dfrac{\pi}{3}. The power factor of the circuit is

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  4. Question 4

    13 May 2026 S1

    138
    In an LCR series circuit, a. c. voltage source is connected in series. When L is removed from the circuit, the phase difference between the voltage and the current is π/3\pi/3. If instead C is removed, the phase difference is again π/3\pi/3. The power factor of the circuit is (tan⁡π3=3)\left(\tan\dfrac{\pi}{3} = \sqrt{3}\right)

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