Rate of heat produced when a loop is pulled through a magnetic field at constant speed
The same question, asked 2 times: 9 May 2023 S2, 9 May 2024 S2. Every wording below, oldest first.
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Question 1
9 May 2023 S2
24A square loop ABCD is moving with constant velocity 'v' in a uniform magnetic field 'B' which is perpendicular to the plane of paper and directed outward. The resistance of coil is 'R', then the rate of production of heat energy in the loop is [L - length of side of loop]Tap an option to check your answer.
Question 2
9 May 2024 S2
17If current is flowing in the closed circuit with collective resistance , the rate of production of heat energy in the loop as we pull it along with a constant speed is ( = length of conductor, = magnetic field)Tap an option to check your answer.