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Rate of heat produced when a loop is pulled through a magnetic field at constant speed

The same question, asked 2 times: 9 May 2023 S2, 9 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    9 May 2023 S2

    24
    A square loop ABCD is moving with constant velocity 'v' in a uniform magnetic field 'B' which is perpendicular to the plane of paper and directed outward. The resistance of coil is 'R', then the rate of production of heat energy in the loop is [L - length of side of loop]

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  2. Question 2

    9 May 2024 S2

    17
    If current II is flowing in the closed circuit with collective resistance RR, the rate of production of heat energy in the loop as we pull it along with a constant speed VV is (LL = length of conductor, BB = magnetic field)

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