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Capacitance with a dielectric slab of thickness t between the plates (formula)

The same question, asked 2 times: May 2021 S1*, 12 May 2026 S1. Every wording below, oldest first.

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  1. Question 1

    May 2021 S1

    15
    Separation between the plates of parallel plate capacitor is dd and the area of each plate is AA. When a slab of material of dielectric constant kk and thickness tt (t<d)(t < d) is introduced between the plates, its capacitance becomes (ε0\varepsilon_0 = permittivity of free space)

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  2. Question 2

    12 May 2026 S1

    127
    A parallel plate air capacitor consists of two metal plates of area AA and separation dd. A slab of thickness tt and dielectric constant 2k2k is inserted between the plates with its faces parallel to the plates. The effective capacitance of the system is (ϵ0\epsilon_0 = permittivity of free space)

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