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Work done in rotating a dipole in a uniform electric field

This type of question, asked 4 times: 3 May 2023 S1, 13 May 2024 S2, 19 Apr 2025 S1, 18 Apr 2026 S1. All 4 questions below, oldest first.

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  1. Question 1

    3 May 2023 S1

    50
    An electric dipole of moment P is lying along a uniform electric field E. The work done in rotating the dipole through π3\frac{\pi}{3} is [sin⁡30∘=0.5, cos⁡30∘=32\sin30^\circ=0.5,\ \cos30^\circ=\frac{\sqrt{3}}{2}]

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  2. Question 2

    13 May 2024 S2

    18
    The work done in rotating a dipole placed parallel to the electric field through 180∘180^\circ is 'ww'. So the work done in rotating it through 60∘60^\circ is (cos⁡0∘=1,cos⁡60∘=12,cos⁡180∘=−1\cos 0^\circ=1,\cos 60^\circ=\frac{1}{2},\cos 180^\circ=-1)

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  3. Question 3

    19 Apr 2025 S1

    44
    An electric dipole of dipole moment ' pp ' is aligned parallel to a uniform electric field ' E '. The energy required to rotate the dipole by 90∘90^{\circ} is [sin⁡0∘=0,sin⁡90∘=1cos⁡0∘=1,cos⁡90∘=0]\begin{bmatrix} \sin0^{\circ}= 0, & \sin90^{\circ}= 1 \\ \cos0^{\circ}= 1, & \cos90^{\circ}= 0 \end{bmatrix}

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  4. Question 4

    18 Apr 2026 S1

    125
    When a dipole placed parallel to electric field is rotating through πc\pi^c, the work done is W. The work done in rotating the dipole through (π3)c\left(\dfrac{\pi}{3}\right)^c is (cos⁡0∘=1,cos⁡60∘=12,cos⁡180∘=−1)\left(\cos 0^\circ = 1, \cos 60^\circ = \dfrac{1}{2}, \cos 180^\circ = -1\right)

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