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Capacitor with two dielectric layers parallel to the plates (in series)

This type of question, asked 5 times: 4 May 2023 S1, 16 May 2023 S2, 10 May 2024 S2, 20 Apr 2025 S2, 14 May 2026 S1. All 5 questions below, oldest first.

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  1. Question 1

    4 May 2023 S1

    2
    A parallel plate air capacitor, with plate separation dd has a capacitance of 9 pF. The space between the plates is now filled with two dielectrics, the first having K1=3K_1 = 3 and thickness d1=d/3d_1 = d/3, while the 2nd has K2=6K_2 = 6 and thickness d2=2d/3d_2 = 2d/3. The capacitance of the new capacitor is

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  2. Question 2

    16 May 2023 S2

    46
    Air capacitor has capacitance C1C_1. The space between two plates of capacitor is filled with two dielectrics as shown in figure. The new capacitance of the capacitor is C2C_2. The ratio C1/C2C_1/C_2 is (d=d = distance between two plates of capacitor, K1K_1 and K2K_2 are dielectric constants)

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  3. Question 3

    10 May 2024 S2

    20
    Two dielectric slabs having dielectric constant 'K1K_1' and 'K2K_2' of thickness 'd4\frac{d}{4}' and '3d4\frac{3d}{4}' are inserted between the plates as shown in figure. The net capacitance between A and B is (ϵ0\epsilon_0 is permittivity of free space)

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  4. Question 4

    20 Apr 2025 S2

    26
    A parallel plate air capacitor has capacitance CPC_{P}. It is equally filled with parallel layers of materials of dielectric constants K1K_{1} and K2K_{2}. Now its capacity becomes CKC_{K}. The ratio CPC_{P} to CKC_{K} is

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  5. Question 5

    14 May 2026 S1

    127
    A parallel plate air capacitor has capacity CC and plate area AA. Now the space between its plates is filled by two slabs of thickness d2\dfrac{d}{2} each, having dielectric constants K1K_1 and K2K_2. Distance of separation between plates is dd. The capacity of the capacitor is (ε0\varepsilon_0 = permittivity of free space)

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