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Frequency of a simple pendulum taken to a depth below the earth's surface

The same question, asked 2 times: 4 May 2023 S2*, 12 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    4 May 2023 S2

    21
    A pendulum is oscillating with frequency 'n' on the surface of earth. If it is taken to a depth R4\frac{R}{4} below the surface of earth, new frequency of oscillation at depth R4\frac{R}{4} is (R=R = radius of earth)

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  2. Question 2

    12 May 2024 S2

    38
    A simple pendulum is oscillating with frequency F on the surface of the earth. It is taken to a depth below the surface of earth (R=R = radius of earth). The frequency of oscillation at depth R/3R/3 is

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