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Value of g or weight at a depth below the earth's surface

This type of question, asked 7 times: May 2022 S1, 11 May 2023 S1, 9 May 2024 S1, 12 May 2024 S2, 13 May 2024 S2, 25 Apr 2025 S2, 26 Apr 2025 S2. All 7 questions below, oldest first.

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  1. Question 1

    May 2022 S1

    3
    A body weighs 500 N on the surface of the earth. At what distance below the surface of the earth it weighs 250 N? (Radius of earth, R=6400R = 6400 km)

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  2. Question 2

    11 May 2023 S1

    25
    The depth 'd' at which the value of acceleration due to gravity becomes 1n−1\frac{1}{n-1} times the value at the earth's surface is (R = radius of the earth)

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  3. Question 3

    9 May 2024 S1

    23
    A body weighs 300 N on the surface of the earth. How much will it weigh at a distance R2\frac{R}{2} below the surface of earth? (R→R\rightarrow Radius of earth)

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  4. Question 4

    12 May 2024 S2

    16
    The depth at which acceleration due to gravity becomes g2n\frac{g}{2n} is (R=R = radius of earth, g=g = acceleration due to gravity on earth's surface, n is integer)

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  5. Question 5

    13 May 2024 S2

    6
    A mine is located at depth R3\frac{R}{3} below earth's surface. The acceleration due to gravity at that depth in mine is (R=R= radius of earth, g=g= acceleration due to gravity)

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  6. Question 6

    25 Apr 2025 S2

    11
    The depth at which the value of acceleration due to gravity becomes (1n)\left( \frac{1}{n} \right) times the value at the surface of the earth is ( R=R = radius of the earth)

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  7. Question 7

    26 Apr 2025 S2

    33
    The depth at which acceleration due to gravity becomes gn\frac{g}{n} is (R=(R = radius of earth, g=g = acceleration due to gravity) ( n=n = integer)

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