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Speed of particles moving in a circle under their mutual gravitational attraction

This type of question, asked 2 times: 19 Apr 2025 S1, 12 May 2026 S1. All 2 questions below, oldest first.

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  1. Question 1

    19 Apr 2025 S1

    19
    Two particles of equal mass ' mm ' move in a circle of radius ' rr ' under the action of their mutual gravitational attraction. The speed of each particle will be ( G=G = Universal gravitational constant)

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  2. Question 2

    12 May 2026 S1

    108
    Four particles, each of mass M and equidistant from each other, move along a circle of radius R under the action of their gravitational attraction, the speed of each particle is {sin⁡(45)0=cos⁡(45)∘=1/(2)0.5}\{\sin(45)^0 = \cos(45)^\circ = 1/(2)^{0.5}\}

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