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L and R in series on a 50 Hz supply with current lagging by pi/3: find R

The same question, asked 2 times: 12 May 2024 S2*, 20 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    12 May 2024 S2

    28
    When an inductor 'LL' and a resistor 'RR' in series are connected across a 15 V, 50 Hz a.c. supply, a current of 0.3 A flows in the circuit. The current differs in phase from the applied voltage by π3\dfrac{\pi}{3}. The value of 'RR' is

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  2. Question 2

    12 May 2024 S2

    13
    An a.c. source of 15 V, 50 Hz is connected across an inductor (L) and a resistance (R) in series. An r.m.s. current of 0.5 A flows in the circuit. The phase difference between the applied voltage and the current is π3\frac{\pi}{3} radian. The value of the resistance (R) is [tan⁡60∘=3\tan 60^\circ = \sqrt{3}]

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  3. Question 3

    20 Apr 2026 S1

    138
    When an inductance 'LL' and resistor 'RR' are connected in series to 2525V, 5050 Hz supply, a current of 0.50.5 A flows in the circuit. The current lags behind in phase from applied voltage by (π3)\left(\dfrac{\pi}{3}\right) radian. The value of R is (cos⁡60∘=12)\left(\cos 60^\circ = \dfrac{1}{2}\right)

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