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Field at the centre of a circular coil (B = mu0 n I / 2R)

This type of question, asked 2 times: 10 May 2024 S2, 22 Apr 2025 S1. All 2 questions below, oldest first.

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  1. Question 1

    10 May 2024 S2

    37
    The magnetic field at the centre of a circular coil of radius 'RR' carrying current 2 A is 'B1B_1'. The magnetic field at the centre of another coil of radius '3R3R' carrying current 4 A4\,A is 'B2B_2'. The ratio B1:B2B_1:B_2 is

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  2. Question 2

    22 Apr 2025 S1

    22
    A circular coil of wire consisting of ' nn ' turns each of radius 8 cm carries a current of 0.4 A . The magnitude of the magnetic field at the centre of coil is 3.14×10−4 T3.14 \times10^{- 4}\text{ }T. The value of ' n ' is [Take μ0=12.56×10−7\mu_{0}= 12.56 \times10^{- 7} SI unit]

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