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Permeability of a rod from flux, area and magnetic intensity (mu = B/H)

This type of question, asked 6 times: 4 May 2023 S2, 13 Apr 2026 S1, 13 Apr 2026 S2, 15 Apr 2026 S2, 13 May 2026 S1, 15 May 2026 S1. All 6 questions below, oldest first.

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  1. Question 1

    4 May 2023 S2

    48
    A magnetic intensity of 500 A/m produces a magnetic flux of 2.4×10−52.4\times10^{-5} Wb in an iron bar of cross-sectional area 0.40.4 cm2^2. The magnetic permeability of the iron bar is

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  2. Question 2

    13 Apr 2026 S1

    131
    An iron rod is placed parallel to magnetic field intensity 2000 A/m. The magnetic flux through rod is 6×10−46 \times 10^{-4} wb and its cross sectional area is 3 cm2\mathrm{cm^2}. The magnetic permeability of the rod in wb/A-m is

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  3. Question 3

    13 Apr 2026 S2

    134
    A rod with a circular cross-section area 2 cm22\ \mathrm{cm^2} and length 4040 cm is wound uniformly with 400400 turns of an insulated wire. If a current 0.40.4 A flows in the wire winding, the total magnetic flux produced inside the winding is 4π×10−64\pi \times 10^{-6} Wb. The relative permeability of the rod is (Given permeability of vacuum μ0=4π×10−7 N m A−2\mu_0 = 4\pi \times 10^{-7}\ \mathrm{N\,m\,A^{-2}})

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  4. Question 4

    15 Apr 2026 S2

    131
    An iron rod is placed parallel to magnetic field intensity 1000 A/m. The magnetic flux through the rod is 3×10−43 \times 10^{-4} Wb and its cross-sectional area is 1.5 cm21.5\ \mathrm{cm^2}. The magnetic permeability of rod in Wb/A-m is

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  5. Question 5

    13 May 2026 S1

    133
    An iron rod is placed parallel to magnetic field of intensity H. The magnetic flux through the rod is Φ\Phi and its cross-sectional area is A. The magnetic permeability (μ)(\mu) of the rod is

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  6. Question 6

    15 May 2026 S1

    133
    A magnetising field of 50005000 A/m produces a magnetic flux of 4×10−54 \times 10^{-5} Wb in an iron rod of cross-sectional area 0.4 cm20.4\ \mathrm{cm^2}. The permeability of the rod (in Wb/Am) is

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