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Water tank and tap: rate dh/dt at which the water level falls

The same question, asked 2 times: 4 May 2023 S1, 13 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    4 May 2023 S1

    31
    The surface of water in a water tank of cross section area 750 cm2750\text{ cm}^2 on the top of a house is hh m above the tap level. The speed of water coming out through the tap of cross section area 500 mm2500\text{ mm}^2 is 30 cm/s30\text{ cm/s}. At that instant dhdt=x×10−3 m/s\frac{dh}{dt} = x \times 10^{-3}\text{ m/s}. The value of xx will be

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  2. Question 2

    13 Apr 2026 S2

    112
    The surface of water in a water tank of cross-section area 750 cm2750\ \mathrm{cm^2} on the top of a house is hh m above the tap level. The speed of water coming out through the tap of cross-section area 500 mm2500\ \mathrm{mm^2} is 3030 cm/s. At that instant, dh/dtdh/dt is y×10−3y \times 10^{-3} m/s. The value of yy will be

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