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E0 cos(wt) applied to an LR circuit with X_L a multiple of R: power consumed

The same question, asked 4 times: 9 May 2023 S2*, 10 May 2023 S1*, 13 May 2024 S2*, 19 Apr 2025 S2. Every wording below, oldest first.

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  1. Question 1

    9 May 2023 S2

    33
    An e.m.f. E=E0cos⁡ωtE = E_0\cos\omega t is applied to circuit containing L and R in series. If XL=2RX_L = 2R, then the power dissipated in the circuit is

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  2. Question 2

    10 May 2023 S1

    7
    An e.m.f. E=E0cos⁡ωtE=E_0\cos\omega t is applied to the L-R circuit. The inductive reactance is equal to the resistance 'R' of the circuit. The power consumed in the circuit is

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  3. Question 3

    13 May 2024 S2

    7
    In a L-R circuit the inductive reactance is equal to the resistance 'RR' in the circuit. An emf E=E0cos⁡ωtE = E_0\cos\omega t is applied to the circuit. The power consumed in the circuit is

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  4. Question 4

    19 Apr 2025 S2

    33
    In an L−RL-R circuit, the inductive reactance is equal to 3\sqrt{3} times the resistance ' RR ' of the circuit. An e.m.f. E=E0sin⁡(ωt)E =E_{0}\sin(\omega t) is applied to the circuit. The power consumed in the circuit is

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