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Focal length or power of a lens immersed in a liquid

This type of question, asked 7 times: 4 May 2023 S2, 14 May 2024 S2, 22 Apr 2025 S2, 26 Apr 2025 S2, 16 Apr 2026 S2, 17 Apr 2026 S1, 18 Apr 2026 S2. All 7 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    4 May 2023 S2

    11
    A convex lens of refractive index 32\frac{3}{2} has a power 2.5. If it is placed in a liquid of refractive index 2, the new power of the lens is

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  2. Question 2

    14 May 2024 S2

    27
    Refractive index of a glass convex lens is 1.5. The radius of curvature of each of the two surfaces is 20 cm. The ratio of the power of the lens when immersed in a liquid of refractive index 1.25 to that when placed in air is

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  3. Question 3

    22 Apr 2025 S2

    37
    A concave lens (refractive index =1.5= 1.5 ) has both surfaces of same radius of curvature R . If it is immersed in a liquid of refractive index 1.75 it will act as a

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  4. Question 4

    26 Apr 2025 S2

    11
    Refractive index of a glass convex lens is 1.5 . The radius of curvature of each of the two surfaces of the lens is 40 cm . The ratio of the power of the lens when immersed in a liquid of refractive index 1.25 o that when placed in air is

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  5. Question 5

    16 Apr 2026 S2

    141
    A convex lens having refractive index 1.6 has focal length 12 cm, when it is in air. The focal length of that lens when placed in water is (refractive index of water = 1.28)

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  6. Question 6

    17 Apr 2026 S1

    140
    A lens of refractive index 'μ\mu' has focal length 'ff'. When the lens is immersed in a liquid of refractive index 'μ0\mu_0', its focal length becomes 'f0f_0'. Then 'f0f_0' is given by

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  7. Question 7

    18 Apr 2026 S2

    140
    Refractive index of a glass convex lens is 1.51.5. The radius of curvature of each of the two surfaces of the lens is 40 cm. The ratio of the power of the lens when immersed in a liquid of refractive index 1.251.25 to that when placed in air is

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