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Velocity varies as 4v^2 = 50 - x^2 and the period is x/7 s: find x

The same question, asked 2 times: 4 May 2023 S1, 13 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    4 May 2023 S1

    4
    The velocity of a particle executing S.H.M. varies with displacement (x)(x) as 4V2=50−x24V^2 = 50 - x^2. The time period of oscillation is x7\frac{x}{7} second. The value of xx is (Take π=227\pi = \frac{22}{7})

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  2. Question 2

    13 Apr 2026 S2

    121
    The velocity of a particle executing SHM varies with displacement (x)(x) as 4v2=50−x24v^2 = 50 - x^2. The time period of oscillations is x/7x/7 s. The value of xx is (Take π=22/7\pi = 22/7)

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